Hi
I have a table with dates stored in a nvarchar(75), I would like to move
this over to datetime (for obvious reasons)
the problem is the field has some 'bad data'
how can i query the nvarchar field to return me anything that isnt a date?
so i can fix and convert
Thanks in advance
MikeMike
Take a look at ISDATE () function
"Mike Fellows" <mike.fellows@.equityhouse.NO.SPAM.co.uk> wrote in message
news:KeadnZwJPKHNSW3anZ2dneKdnZydnZ2d@.giganews.com...
> Hi
> I have a table with dates stored in a nvarchar(75), I would like to move
> this over to datetime (for obvious reasons)
> the problem is the field has some 'bad data'
> how can i query the nvarchar field to return me anything that isnt a date?
> so i can fix and convert
> Thanks in advance
> Mike
>|||Uri,
I have been looking at that all morning and trying to understand it fully.
using the following query
SELECT MyDate, ISDATE(CommissionDate) AS Expr1 FROM MyTable
this returns a 1 or 0
the problem with ISDATE() is that it seems to rely on an american date
format
so 13/02/2003 is invalid whereas 02/13/2003 is valid
being in the UK the function appears to be as much use as a chocolate fire
guard :)
Thanks
Mike
"Uri Dimant" <urid@.iscar.co.il> wrote in message
news:OTLvllykIHA.5660@.TK2MSFTNGP02.phx.gbl...
> Mike
> Take a look at ISDATE () function
>
> "Mike Fellows" <mike.fellows@.equityhouse.NO.SPAM.co.uk> wrote in message
> news:KeadnZwJPKHNSW3anZ2dneKdnZydnZ2d@.giganews.com...
>> Hi
>> I have a table with dates stored in a nvarchar(75), I would like to move
>> this over to datetime (for obvious reasons)
>> the problem is the field has some 'bad data'
>> how can i query the nvarchar field to return me anything that isnt a
>> date? so i can fix and convert
>> Thanks in advance
>> Mike
>|||the UK problem can be fixed by using
SET DATEFORMAT dmy;
- got it working now
Thanks again
Mike
"Mike Fellows" <mike.fellows@.equityhouse.NO.SPAM.co.uk> wrote in message
news:UpudnVw4esuFQG3anZ2dnUVZ8v6dnZ2d@.giganews.com...
> Uri,
> I have been looking at that all morning and trying to understand it fully.
> using the following query
> SELECT MyDate, ISDATE(CommissionDate) AS Expr1 FROM MyTable
> this returns a 1 or 0
> the problem with ISDATE() is that it seems to rely on an american date
> format
> so 13/02/2003 is invalid whereas 02/13/2003 is valid
> being in the UK the function appears to be as much use as a chocolate fire
> guard :)
> Thanks
> Mike
>
>
> "Uri Dimant" <urid@.iscar.co.il> wrote in message
> news:OTLvllykIHA.5660@.TK2MSFTNGP02.phx.gbl...
>> Mike
>> Take a look at ISDATE () function
>>
>> "Mike Fellows" <mike.fellows@.equityhouse.NO.SPAM.co.uk> wrote in message
>> news:KeadnZwJPKHNSW3anZ2dneKdnZydnZ2d@.giganews.com...
>> Hi
>> I have a table with dates stored in a nvarchar(75), I would like to move
>> this over to datetime (for obvious reasons)
>> the problem is the field has some 'bad data'
>> how can i query the nvarchar field to return me anything that isnt a
>> date? so i can fix and convert
>> Thanks in advance
>> Mike
>>
>
Showing posts with label datetime. Show all posts
Showing posts with label datetime. Show all posts
Friday, March 30, 2012
Monday, March 26, 2012
query
drop table share
create table share
(
shid int identity ,
dt datetime,
price int
)
insert into share(dt,price) values('1-jan-2006',10)
insert into share(dt,price) values('2-jan-2006',11)
insert into share(dt,price) values('6-jan-2006',15)
insert into share(dt,price) values('4-jan-2006',9)
select * from share
output i want is
the difference in share prices from the previous day.
so
1 (11-10)
4 (15-11)
-6 (9-15)
select top 100 percent p1.shid p1shid, p2.shid p2shid, p1.price p1price,
p2.price p2price
from
(select * from share
) as p2,
share p1
where p1.shid < p2.shid
order by p1.shid, p2.shid
thisis the closest i could come up with but it has duplicates.Try,
select b.price - a.price
from t1 as a inner join t1 as b
on a.dt = (select max(c.dt) from t1 as c where c.dt < b.dt)
Why 15 - 11 and 9 - 15 instead 9 - 11 and 15 - 9?. If you meant previous
[shid] then try:
select b.price - a.price
from t1 as a inner join t1 as b
on a.shid = (select max(c.shid) from t1 as c where c.shid < b.shid)
AMB
"ichor" wrote:
> drop table share
> create table share
> (
> shid int identity ,
> dt datetime,
> price int
> )
>
> insert into share(dt,price) values('1-jan-2006',10)
> insert into share(dt,price) values('2-jan-2006',11)
> insert into share(dt,price) values('6-jan-2006',15)
> insert into share(dt,price) values('4-jan-2006',9)
> select * from share
>
> output i want is
>
> the difference in share prices from the previous day.
> so
> 1 (11-10)
> 4 (15-11)
> -6 (9-15)
>
> select top 100 percent p1.shid p1shid, p2.shid p2shid, p1.price p1price,
> p2.price p2price
> from
> (select * from share
> ) as p2,
> share p1
> where p1.shid < p2.shid
> order by p1.shid, p2.shid
> thisis the closest i could come up with but it has duplicates.
>
>|||u r right. sorry for the mistake.
the query works fine.
the first query is what i was after.
i guess my approach of writing the query was wrong
"Alejandro Mesa" <AlejandroMesa@.discussions.microsoft.com> wrote in message
news:73C20DA8-65E8-4203-BD0A-AF90394834A5@.microsoft.com...
> Try,
> select b.price - a.price
> from t1 as a inner join t1 as b
> on a.dt = (select max(c.dt) from t1 as c where c.dt < b.dt)
> Why 15 - 11 and 9 - 15 instead 9 - 11 and 15 - 9?. If you meant previous
> [shid] then try:
> select b.price - a.price
> from t1 as a inner join t1 as b
> on a.shid = (select max(c.shid) from t1 as c where c.shid < b.shid)
>
> AMB
> "ichor" wrote:
>|||I think this should work:
select shid, dt, price - isnull((Select price from share b where b.shid =
a.shid - 1), 0) from share a
Hope this help...
Ed
"ichor" wrote:
> drop table share
> create table share
> (
> shid int identity ,
> dt datetime,
> price int
> )
>
> insert into share(dt,price) values('1-jan-2006',10)
> insert into share(dt,price) values('2-jan-2006',11)
> insert into share(dt,price) values('6-jan-2006',15)
> insert into share(dt,price) values('4-jan-2006',9)
> select * from share
>
> output i want is
>
> the difference in share prices from the previous day.
> so
> 1 (11-10)
> 4 (15-11)
> -6 (9-15)
>
> select top 100 percent p1.shid p1shid, p2.shid p2shid, p1.price p1price,
> p2.price p2price
> from
> (select * from share
> ) as p2,
> share p1
> where p1.shid < p2.shid
> order by p1.shid, p2.shid
> thisis the closest i could come up with but it has duplicates.
>
>|||can u explain why we need a b and c?
in the query?
"ichor" <ichor@.hotmail.com> wrote in message
news:Oe6jYSxRGHA.792@.TK2MSFTNGP10.phx.gbl...
>u r right. sorry for the mistake.
> the query works fine.
> the first query is what i was after.
> i guess my approach of writing the query was wrong
> "Alejandro Mesa" <AlejandroMesa@.discussions.microsoft.com> wrote in
> message news:73C20DA8-65E8-4203-BD0A-AF90394834A5@.microsoft.com...
>|||We need to join a tabla to itself, so we need to alias the second reference
to it (b). The join condition is between a row in one side (b) and the a row
in the other side (a) where its [dt] value (in a) is equal to the previous of
current in b (the max([c.dt]) where [dt] < b.[dt]).
AMB
"ichor" wrote:
> can u explain why we need a b and c?
> in the query?
> "ichor" <ichor@.hotmail.com> wrote in message
> news:Oe6jYSxRGHA.792@.TK2MSFTNGP10.phx.gbl...
>
>|||could we have done this using only a and b and no c?
"Alejandro Mesa" <AlejandroMesa@.discussions.microsoft.com> wrote in message
news:3AD01065-EBAA-4AAE-990C-E1F29FB8BD9B@.microsoft.com...
> We need to join a tabla to itself, so we need to alias the second
> reference
> to it (b). The join condition is between a row in one side (b) and the a
> row
> in the other side (a) where its [dt] value (in a) is equal to the previous
> of
> current in b (the max([c.dt]) where [dt] < b.[dt]).
>
> AMB
> "ichor" wrote:
>
create table share
(
shid int identity ,
dt datetime,
price int
)
insert into share(dt,price) values('1-jan-2006',10)
insert into share(dt,price) values('2-jan-2006',11)
insert into share(dt,price) values('6-jan-2006',15)
insert into share(dt,price) values('4-jan-2006',9)
select * from share
output i want is
the difference in share prices from the previous day.
so
1 (11-10)
4 (15-11)
-6 (9-15)
select top 100 percent p1.shid p1shid, p2.shid p2shid, p1.price p1price,
p2.price p2price
from
(select * from share
) as p2,
share p1
where p1.shid < p2.shid
order by p1.shid, p2.shid
thisis the closest i could come up with but it has duplicates.Try,
select b.price - a.price
from t1 as a inner join t1 as b
on a.dt = (select max(c.dt) from t1 as c where c.dt < b.dt)
Why 15 - 11 and 9 - 15 instead 9 - 11 and 15 - 9?. If you meant previous
[shid] then try:
select b.price - a.price
from t1 as a inner join t1 as b
on a.shid = (select max(c.shid) from t1 as c where c.shid < b.shid)
AMB
"ichor" wrote:
> drop table share
> create table share
> (
> shid int identity ,
> dt datetime,
> price int
> )
>
> insert into share(dt,price) values('1-jan-2006',10)
> insert into share(dt,price) values('2-jan-2006',11)
> insert into share(dt,price) values('6-jan-2006',15)
> insert into share(dt,price) values('4-jan-2006',9)
> select * from share
>
> output i want is
>
> the difference in share prices from the previous day.
> so
> 1 (11-10)
> 4 (15-11)
> -6 (9-15)
>
> select top 100 percent p1.shid p1shid, p2.shid p2shid, p1.price p1price,
> p2.price p2price
> from
> (select * from share
> ) as p2,
> share p1
> where p1.shid < p2.shid
> order by p1.shid, p2.shid
> thisis the closest i could come up with but it has duplicates.
>
>|||u r right. sorry for the mistake.
the query works fine.
the first query is what i was after.
i guess my approach of writing the query was wrong
"Alejandro Mesa" <AlejandroMesa@.discussions.microsoft.com> wrote in message
news:73C20DA8-65E8-4203-BD0A-AF90394834A5@.microsoft.com...
> Try,
> select b.price - a.price
> from t1 as a inner join t1 as b
> on a.dt = (select max(c.dt) from t1 as c where c.dt < b.dt)
> Why 15 - 11 and 9 - 15 instead 9 - 11 and 15 - 9?. If you meant previous
> [shid] then try:
> select b.price - a.price
> from t1 as a inner join t1 as b
> on a.shid = (select max(c.shid) from t1 as c where c.shid < b.shid)
>
> AMB
> "ichor" wrote:
>|||I think this should work:
select shid, dt, price - isnull((Select price from share b where b.shid =
a.shid - 1), 0) from share a
Hope this help...
Ed
"ichor" wrote:
> drop table share
> create table share
> (
> shid int identity ,
> dt datetime,
> price int
> )
>
> insert into share(dt,price) values('1-jan-2006',10)
> insert into share(dt,price) values('2-jan-2006',11)
> insert into share(dt,price) values('6-jan-2006',15)
> insert into share(dt,price) values('4-jan-2006',9)
> select * from share
>
> output i want is
>
> the difference in share prices from the previous day.
> so
> 1 (11-10)
> 4 (15-11)
> -6 (9-15)
>
> select top 100 percent p1.shid p1shid, p2.shid p2shid, p1.price p1price,
> p2.price p2price
> from
> (select * from share
> ) as p2,
> share p1
> where p1.shid < p2.shid
> order by p1.shid, p2.shid
> thisis the closest i could come up with but it has duplicates.
>
>|||can u explain why we need a b and c?
in the query?
"ichor" <ichor@.hotmail.com> wrote in message
news:Oe6jYSxRGHA.792@.TK2MSFTNGP10.phx.gbl...
>u r right. sorry for the mistake.
> the query works fine.
> the first query is what i was after.
> i guess my approach of writing the query was wrong
> "Alejandro Mesa" <AlejandroMesa@.discussions.microsoft.com> wrote in
> message news:73C20DA8-65E8-4203-BD0A-AF90394834A5@.microsoft.com...
>|||We need to join a tabla to itself, so we need to alias the second reference
to it (b). The join condition is between a row in one side (b) and the a row
in the other side (a) where its [dt] value (in a) is equal to the previous of
current in b (the max([c.dt]) where [dt] < b.[dt]).
AMB
"ichor" wrote:
> can u explain why we need a b and c?
> in the query?
> "ichor" <ichor@.hotmail.com> wrote in message
> news:Oe6jYSxRGHA.792@.TK2MSFTNGP10.phx.gbl...
>
>|||could we have done this using only a and b and no c?
"Alejandro Mesa" <AlejandroMesa@.discussions.microsoft.com> wrote in message
news:3AD01065-EBAA-4AAE-990C-E1F29FB8BD9B@.microsoft.com...
> We need to join a tabla to itself, so we need to alias the second
> reference
> to it (b). The join condition is between a row in one side (b) and the a
> row
> in the other side (a) where its [dt] value (in a) is equal to the previous
> of
> current in b (the max([c.dt]) where [dt] < b.[dt]).
>
> AMB
> "ichor" wrote:
>
Friday, March 23, 2012
QUERY
Using sql 2000 here is my table, query, and error
Table
create table projec
(task varchar(14) not null
startdate datetime
enddate datetime)
Query
SELECT TASK "TASKS_SHORTER_THAN_ONE_MONTH
FROM PROJEC
WHERE ADD_MONTHS (STARTDATE,1) > ENDDATE
Error
Server: Msg 195, Level 15, State 10, Line
'ADD_MONTHS' is not a recognized function nameI think you want this
SELECT TASK as 'TASKS_SHORTER_THAN_ONE_MONTH'
FROM PROJECT
WHERE datediff(m,STARTDATE, ENDDATE) < 1
of if you wanted days use
WHERE datediff(dd,STARTDATE, ENDDATE) < 30
Download BOL, it will help immensely -
http://www.microsoft.com/downloads/details.aspx?FamilyID=a6f79cb1-a420-445f-8a4b-bd77a7da194b&DisplayLang=en
HTH
--
Ray Higdon MCSE, MCDBA, CCNA
--
"RMSANDS" <anonymous@.discussions.microsoft.com> wrote in message
news:48E0A71C-7E83-47D6-8838-C4271F0EB6B8@.microsoft.com...
> Using sql 2000 here is my table, query, and error.
> Table:
> create table project
> (task varchar(14) not null,
> startdate datetime,
> enddate datetime);
>
> Query:
> SELECT TASK "TASKS_SHORTER_THAN_ONE_MONTH"
> FROM PROJECT
> WHERE ADD_MONTHS (STARTDATE,1) > ENDDATE;
> Error:
> Server: Msg 195, Level 15, State 10, Line 3
> 'ADD_MONTHS' is not a recognized function name.
>
Table
create table projec
(task varchar(14) not null
startdate datetime
enddate datetime)
Query
SELECT TASK "TASKS_SHORTER_THAN_ONE_MONTH
FROM PROJEC
WHERE ADD_MONTHS (STARTDATE,1) > ENDDATE
Error
Server: Msg 195, Level 15, State 10, Line
'ADD_MONTHS' is not a recognized function nameI think you want this
SELECT TASK as 'TASKS_SHORTER_THAN_ONE_MONTH'
FROM PROJECT
WHERE datediff(m,STARTDATE, ENDDATE) < 1
of if you wanted days use
WHERE datediff(dd,STARTDATE, ENDDATE) < 30
Download BOL, it will help immensely -
http://www.microsoft.com/downloads/details.aspx?FamilyID=a6f79cb1-a420-445f-8a4b-bd77a7da194b&DisplayLang=en
HTH
--
Ray Higdon MCSE, MCDBA, CCNA
--
"RMSANDS" <anonymous@.discussions.microsoft.com> wrote in message
news:48E0A71C-7E83-47D6-8838-C4271F0EB6B8@.microsoft.com...
> Using sql 2000 here is my table, query, and error.
> Table:
> create table project
> (task varchar(14) not null,
> startdate datetime,
> enddate datetime);
>
> Query:
> SELECT TASK "TASKS_SHORTER_THAN_ONE_MONTH"
> FROM PROJECT
> WHERE ADD_MONTHS (STARTDATE,1) > ENDDATE;
> Error:
> Server: Msg 195, Level 15, State 10, Line 3
> 'ADD_MONTHS' is not a recognized function name.
>
QUERY
Using sql 2000 here is my table, query, and error.
Table:
create table project
(task varchar(14) not null,
startdate datetime,
enddate datetime);
Query:
SELECT TASK "TASKS_SHORTER_THAN_ONE_MONTH"
FROM PROJECT
WHERE ADD_MONTHS (STARTDATE,1) > ENDDATE;
Error:
Server: Msg 195, Level 15, State 10, Line 3
'ADD_MONTHS' is not a recognized function name.I think you want this
SELECT TASK as 'TASKS_SHORTER_THAN_ONE_MONTH'
FROM PROJECT
WHERE datediff(m,STARTDATE, ENDDATE) < 1
of if you wanted days use
WHERE datediff(dd,STARTDATE, ENDDATE) < 30
Download BOL, it will help immensely -
http://www.microsoft.com/downloads/...&DisplayLang=en
HTH
Ray Higdon MCSE, MCDBA, CCNA
--
"RMSANDS" <anonymous@.discussions.microsoft.com> wrote in message
news:48E0A71C-7E83-47D6-8838-C4271F0EB6B8@.microsoft.com...
> Using sql 2000 here is my table, query, and error.
> Table:
> create table project
> (task varchar(14) not null,
> startdate datetime,
> enddate datetime);
>
> Query:
> SELECT TASK "TASKS_SHORTER_THAN_ONE_MONTH"
> FROM PROJECT
> WHERE ADD_MONTHS (STARTDATE,1) > ENDDATE;
> Error:
> Server: Msg 195, Level 15, State 10, Line 3
> 'ADD_MONTHS' is not a recognized function name.
>
Table:
create table project
(task varchar(14) not null,
startdate datetime,
enddate datetime);
Query:
SELECT TASK "TASKS_SHORTER_THAN_ONE_MONTH"
FROM PROJECT
WHERE ADD_MONTHS (STARTDATE,1) > ENDDATE;
Error:
Server: Msg 195, Level 15, State 10, Line 3
'ADD_MONTHS' is not a recognized function name.I think you want this
SELECT TASK as 'TASKS_SHORTER_THAN_ONE_MONTH'
FROM PROJECT
WHERE datediff(m,STARTDATE, ENDDATE) < 1
of if you wanted days use
WHERE datediff(dd,STARTDATE, ENDDATE) < 30
Download BOL, it will help immensely -
http://www.microsoft.com/downloads/...&DisplayLang=en
HTH
Ray Higdon MCSE, MCDBA, CCNA
--
"RMSANDS" <anonymous@.discussions.microsoft.com> wrote in message
news:48E0A71C-7E83-47D6-8838-C4271F0EB6B8@.microsoft.com...
> Using sql 2000 here is my table, query, and error.
> Table:
> create table project
> (task varchar(14) not null,
> startdate datetime,
> enddate datetime);
>
> Query:
> SELECT TASK "TASKS_SHORTER_THAN_ONE_MONTH"
> FROM PROJECT
> WHERE ADD_MONTHS (STARTDATE,1) > ENDDATE;
> Error:
> Server: Msg 195, Level 15, State 10, Line 3
> 'ADD_MONTHS' is not a recognized function name.
>
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